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-4x^2=6x^2-9
We move all terms to the left:
-4x^2-(6x^2-9)=0
We get rid of parentheses
-4x^2-6x^2+9=0
We add all the numbers together, and all the variables
-10x^2+9=0
a = -10; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·(-10)·9
Δ = 360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{360}=\sqrt{36*10}=\sqrt{36}*\sqrt{10}=6\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{10}}{2*-10}=\frac{0-6\sqrt{10}}{-20} =-\frac{6\sqrt{10}}{-20} =-\frac{3\sqrt{10}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{10}}{2*-10}=\frac{0+6\sqrt{10}}{-20} =\frac{6\sqrt{10}}{-20} =\frac{3\sqrt{10}}{-10} $
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